Multiple choice

The age of father is 3 times of age of his son. 10 years before, the age of the father was 7 times the age of his son. The age of the father is-

  1. 15 years

  2. 45 years

  3. 48 years

  4. 54 years
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let son's present age = s, father's present age = f. Given f = 3s. Ten years ago: f - 10 = 7(s - 10). Substituting f = 3s: 3s - 10 = 7s - 70. Solving: 60 = 4s, so s = 15 and f = 45. Option D (54) would give son = 18, but 10 years ago father would be 44 and son 8, with ratio 44/8 = 5.5, not 7. Option C (48) would give son = 16, and 10 years ago ratio would be 38/6 = 6.33, not 7.

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