A train covered a certain distance at a uniform speed. If the train had been 6 km/h faster, then it would have taken 8 hours less than the scheduled time. And, if the train were slower by 6 km/h, then the train would have taken 12 hours more than the scheduled time. 140% of the length of the journey is

Let the original speed be v km/h and distance be D km. Original time = D/v. With speed (v+6): time = D/(v+6) = D/v - 8. With speed (v-6): time = D/(v-6) = D/v + 12. This gives us two equations: D/(v+6) = D/v - 8 and D/(v-6) = D/v + 12. Solving this system gives v = 30 km/h and D = 1440 km. 140% of D = 1.4 × 1440 = 2016 km.