The length of two parallel chords of a circle of radius 5 cm are 6 cm and 8 cm in the same side of the centre. The distance between them is.

For a chord of length L in a circle of radius R, the perpendicular distance from the center is √(R² - (L/2)²). For the 6 cm chord: distance = √(25 - 9) = √16 = 4 cm from center. For the 8 cm chord: distance = √(25 - 16) = √9 = 3 cm from center. Since both chords are on the same side, the distance between them is 4 - 3 = 1 cm.