Multiple choice

In present A's age is three times of B's age. After seven years, A's age will be two times of B's age then after another 14 years, A's age will be how many times of B's age?

  1. 1

  2. 2

  3. 3

  4. 3.5

  5. 1.5
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Let A=3x and B=x currently. After 7 years: A=3x+7, B=x+7. Given 3x+7 = 2(x+7), so x=7. After 21 years (7+14): A=3x+21=42, B=x+21=28. 42/28 = 1.5, so A's age is 1.5 times B's age. Option E is correct.

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