Multiple choice

The tangents drawn at the points A and B of a circle centered at O meet at P. If ∠AOB = 120o, then ∠APB : ∠APO is -

  1. 3:2

  2. 4:1

  3. 2:1

  4. 2:5

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For tangents PA and PB from point P to a circle with center O, angle between tangents ∠APB = 180° - ∠AOB = 180° - 120° = 60°. Since triangle APO is right-angled at A and ∠AOP = 60°/2 = 30°, we get ∠APO = 60°. Therefore ∠APB : ∠APO = 60° : 30° = 2:1.