In any triangle, the angle at the center (circumcentre) is twice the angle at the circumference subtended by the same arc. Given ∠BAC = 50°, the central angle ∠BOC = 2 × 50° = 100°. Since O is the circumcentre, OB = OC (both are radii), so triangle OBC is isosceles. Therefore, ∠OBC = (180° - 100°)/2 = 40°. This uses the central angle theorem and properties of isosceles triangles.