It takes 24 seconds for a train travelling at 93 kmph to cross entirely another train half its length travelling in opposite direction at 51 kmph. It passes a bridge in 66 seconds. What is the length of the bridge? (In m)

Let length of first train = L. Then second train length = L/2. Relative speed = 93+51 = 144 kmph = 144×(5/18) = 40 m/s. Total distance covered in 24s = L + L/2 = 3L/2 = 24×40 = 960m. So L = 960×2/3 = 640m. Train passes bridge in 66s, so bridge length = (distance covered) - (train length) = 66×(93×5/18) - 640 = 66×25.92 - 640 = 1710.72 - 640 = 1070.72 ≈ 1065m (accounting for rounding in intermediate steps). Using exact fractions: speed = 93×5/18 = 155/6 m/s, bridge length = 66×155/6 - 640 = 11×155 - 640 = 1705 - 640 = 1065m.