Multiple choice

14 years ago, a father was three times as old as his son. Now the father is only twice as old as his son. Then the sum of the present ages of the son and father is -

  1. 84 years

  2. 60 years

  3. 42 years

  4. 28 years
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let present ages be F (father) and S (son). 14 years ago: F-14 = 3(S-14), so F = 3S-28. Now: F = 2S. Solving gives S = 28, F = 56. Sum = 84 years. Answer A is correct.

Keep practicing — related questions