Multiple choice

The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. Find the ratio of their present ages ?

  1. 7:3

  2. 2:5

  3. 6:7

  4. 2:4

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A Correct answer
Explanation

Let present ages be F (father) and S (son). 10 years ago: F-10 = 3(S-10). In 10 years: F+10 = 2(S+10). From first: F = 3S-20. Substituting: 3S-20+10 = 2S+20, giving 3S-10 = 2S+20, so S = 30, F = 70. Ratio F:S = 70:30 = 7:3.