Multiple choice

A is 6 times as old as B. A's age will be twice of C's age after 10 years. If C's 7th birthday was celebrated 3 years ago, what is B's present age?

  1. 6 year

  2. 4 year

  3. 5 year

  4. 3 year

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

C's 7th birthday was 3 years ago, so C's present age = 7 + 3 = 10 years. After 10 years, C's age = 20 years. At that time, A's age will be twice C's age, so A's age after 10 years = 2 × 20 = 40 years. Therefore, A's present age = 40 - 10 = 30 years. A is 6 times as old as B, so B = 30/6 = 5 years. The claimed answer C is correct.