The calendar for the year 3009 will be the same for which year?

For calendar repetition, calculate total offset days. 3009 is not a leap year (3009 not divisible by 4, not century year divisible by 400). Check each option: 3015 is 6 years later with 1 leap year (3012). Total offset = 6×365 + 1 = 2191 days = 312 weeks + 7 days = 312 weeks + 1 day. Wait, that's not matching. Let me recalculate: From 3009 to 3015: years 3010, 3011, 3012 (leap), 3013, 3014, 3015. That's 6 years with 1 leap year (3012). Days = 6×365 + 1 = 2191. 2191 mod 7 = 2191 - 312×7 = 2191 - 2184 = 7, which is 0 mod 7. Actually wait, 2191 ÷ 7 = 313 exactly with remainder 0. Let me verify: 313 × 7 = 2191. Yes, so offset is 0 days. This means calendars repeat. Check 3009 starting day: 3009 = 3008 + 1. 3008 is divisible by 400? No. Let me use formula. Actually, simpler: total days from Jan 1, 3009 to Jan 1, 3015 = 2191. 2191 mod 7 = 0. So same calendar. The answer A is correct.