Multiple choice

The digits of a three-digit number are in A.P. When the number is reversed, the number increases by 396. When divided by 50 it gives a remainder of 7. What is the sum of digits?

  1. 12

  2. 15

  3. 18

  4. 21
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the number be abc with digits in AP. Reversing increases by 396: 100c+10b+a = 100a+10b+c+396 → 99(c-a)=396 → c-a=4. Since number ≡7 (mod 50), it ends in 07 or 57. With digits in AP and c-a=4, the number is 357 (3,5,7 in AP with d=2). Sum of digits = 15.

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