Multiple choice

Find the largest number of two digits so that by dividing 211 and 396, the same remainder is obtained?

  1. 36

  2. 37

  3. 39

  4. 42
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

We need the largest 2-digit number that divides (396-211) = 185. Divisors of 185 = 5 × 37. The largest 2-digit divisor is 37. When 211 and 396 are divided by 37, both give remainder 30. This works because numbers with the same remainder have their difference divisible by that number.

Keep practicing — related questions