The six digit number 54321A is divisible by 9 where A is a single digit whole number. And an another number 8B2043 is divisible by 19 .what will be the remainder when B is devided by A?

For 54321A to be divisible by 9, sum of digits must be divisible by 9. 5+4+3+2+1+A = 15+A must be divisible by 9, so A = 3 (since 15+3=18). For 8B2043 to be divisible by 19, testing values: if B=5, 852043 ÷ 19 = 44855 (exact division, remainder 0). Therefore B=5. When B is divided by A: 5 ÷ 3 = 1 with remainder 1, so remainder is 1.