Multiple choice

What is the approximate value of ( (1.929)^{3} + (0.071)^{3} + (0.4108 \times 2) )?

  1. 8

  2. 9

  3. 10

  4. 7

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Use the algebraic identity for (a+b)³ = a³ + b³ + 3ab(a+b). Notice that 1.929 + 0.071 = 2. So the expression equals (2)³ + 0.4108 × 2 - 3(1.929)(0.071)(2). Since (1.929)(0.071) ≈ 0.1369 and 3 × 0.1369 × 2 ≈ 0.8214, we get 8 + 0.8216 - 0.8214 ≈ 8.0002, approximately 8.