Multiple choice

Find the least number of 5 digits which when divided by 12, 15 and 18 leaves a remainder of 9, 12 and 15. 5 अंकों की छोटी से छोटी संख्या ज्ञात कीजिए जिसे 12, 15 और 18 से विभाजित करने पर क्रमशः 9, 12 तथा 15 शेषफल बचे।

  1. 10087

  2. 10077

  3. 10027

  4. 10057

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

LCM of 12,15,18 is 180. Required number = 180k - 3 (since remainders 9,12,15 are each 3 less than divisors). Smallest 5-digit: 180*56 - 3 = 10080 - 3 = 10077. Check: 10077/12=839 R9, 10077/15=671 R12, 10077/18=559 R15.