Multiple choice

In an FBT recruitment class, the average weight of 48 candidates is 70 kg. If the heaviest candidate and the candidate who is 50 kg are rejected, then the average weight drops by 2 kg. Find the weight of the heaviest candidate.

  1. 76 kg

  2. 182 kg

  3. 112 kg

  4. 220 kg

  5. 190 kg
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Initial total weight = 48 * 70 = 3360. After removing two, weight = 46 * 68 = 3128. The sum of the two removed is 3360 - 3128 = 232. If one is 50, the other is 232 - 50 = 182.

AI explanation

The total weight of the 48 candidates is 48 times 70, which equals 3360 kg. When the two candidates are rejected, 46 candidates remain and their new average is 68 kg (70 - 2). Their combined weight is 46 times 68, which equals 3128 kg. The weight of the heaviest candidate is the total reduction minus the 50 kg candidate, calculated as (3360 - 3128) - 50, resulting in 182 kg.

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