Multiple choice

Water flows from a pipe of sectional area 500 cm2 at the rate of 8 m/min. How long would it take to fill a tank whose dimensions are 6 m × 4 m × 4 m?

  1. 6 hr

  2. 5 hr

  3. 4 hr

  4. 2 hr

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Volume of tank = 6 * 4 * 4 = 96 m^3. Flow rate = 500 cm^2 * 8 m/min = 0.05 m^2 * 8 m/min = 0.4 m^3/min. Time = 96 / 0.4 = 240 minutes = 4 hours.

AI explanation

First convert the cross sectional area of the pipe from square centimeters to square meters, which gives 500 divided by 10000, or 0.05 square meters. Using the volume flow rate formula, the rate is area multiplied by velocity, so 0.05 multiplied by 8 gives 0.4 cubic meters per minute. The volume of the tank is 6 multiplied by 4 multiplied by 4, which equals 96 cubic meters. The time required is the tank volume divided by the flow rate, which is 96 divided by 0.4, resulting in 240 minutes. Converting this to hours gives 4 hours.