Multiple choice

A trapezium shaped tank is filled with a pipe with water flowing at the rate of 3.6 km/hr. The length of the tank is 1.25 m and the top and bottom are 20 m and 10 m, respectively. How much water can be filled in the tank in 20 minutes?

  1. 13000 m3

  2. 12250 m3

  3. 22500 m3

  4. 11000 m3
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Flow rate = 3.6 km/hr = 1 m/s. In 20 minutes (1200 seconds), water length = 1200 m. Area of trapezium cross-section = (20 + 10) / 2 * 1.25 = 15 * 1.25 = 18.75 m^2. Volume = Area * length = 18.75 * 1200 = 22500 m^3.

AI explanation

First, find the cross sectional area of the trapezium shaped tank using the formula one half multiplied by the sum of the parallel sides multiplied by the height, which is 0.5 times the quantity 20 plus 10 multiplied by 1.25, giving 18.75 square meters. Convert the flow speed to meters per minute, which is 3.6 km per hr multiplied by 1000 and divided by 60, resulting in 60 meters per minute. The volume flow rate is 60 multiplied by 18.75, or 1125 cubic meters per minute. In 20 minutes, the water filled is 1125 multiplied by 20, which equals 22500 cubic meters.

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