Multiple choice

Two cars X and Y start running at the same time respectively at the speeds of 20 km/hr and 5 km/hr in the opposite directions on the same road. Butterfly A sitting on the car X leaves the car and starts moving towards the car Y with the speed of 55 km/hr, touches the car Y and returns back to car X. This process is repeated till both the cars just cross each other. Initially, the distance between the two cars is 400 km. Find the distance travelled by the butterfly, if it starts at the same time as the two cars start running and doesn't take halts.

  1. 1180 km

  2. 880 km

  3. 1280 km

  4. 900 km

  5. 320 km
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The cars approach each other at a relative speed of 20 + 5 = 25 km/hr. The time taken for them to meet is 400 / 25 = 16 hours. Since the butterfly flies at a constant speed of 55 km/hr during this entire time, the total distance it covers is 55 * 16 = 880 km.

AI explanation

The relative speed of the two cars moving in opposite directions is 20 + 5 = 25 km/hr. Using the formula time equals distance divided by speed, the total time until the cars cross each other is 400 km divided by 25 km/hr, which equals 16 hours. Since the butterfly travels continuously at 55 km/hr during this time, the total distance it covers is 55 multiplied by 16, resulting in 880 km.

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