A mixture is composed of 11 parts of pure milk and 2 parts of water. If 35 litres of water were added to the mixture, then the new mixture would contain twice as much pure milk as water. How much pure milk (in litres) does the original mixture contain?

Let the common multiplier for the mixture parts be x, meaning the original mixture contains 11x litres of milk and 2x litres of water. After adding 35 litres of water, the new mixture must have twice as much milk as water, so 11x = 2(2x + 35). Solving this equation, 11x = 4x + 70, which gives 7x = 70 and x = 10. The original mixture contains 11 times 10, which is 110 litres of pure milk.

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