Multiple choice

There are two alcohol-water solutions, namely S1 and S2. The ratios of alcohol to water in S1 and S2 are 2 : 3 and 4 : 5, respectively. The two solutions are mixed in the ratio of 6 : 7 and the resulting mixture is then sold at Rs. 30 per litre. If the cost price of pure alcohol is Rs. 40 per litre, then what is the profit percentage? (Assume that water comes free of cost)

  1. 72%

  2. 71.68%

  3. 70.83%

  4. 76.92%
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D Correct answer
Explanation

Calculate the amount of alcohol in the mixture using the given ratios and mixing proportions. The cost price is determined by the alcohol content, and profit percentage is (Selling Price - Cost Price) / Cost Price.

AI explanation

Let 6 litres of S1 and 7 litres of S2 be mixed, totaling 13 litres. S1 contains 6 multiplied by 2 divided by 5, equaling 2.4 litres of alcohol, and S2 contains 7 multiplied by 4 divided by 9, equaling 3.11 litres of alcohol. The total alcohol is 5.51 litres, making the cost price of the mixture 5.51 multiplied by Rs. 40, which is Rs. 220.4 for 13 litres, or Rs. 16.95 per litre. Selling this at Rs. 30 per litre gives a profit percentage of ((30 minus 16.95) divided by 16.95) multiplied by 100, which equals 76.92%.

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