Multiple choice

What will be the area of a given cricket ground if a ground level machine in a cylindrical shape, having a radius of 49 cm and length 160 cm, needs 600 revolutions to complete its levelling?

  1. 2956.7 m2

  2. 2956.8 m2

  3. 2956.9 m2

  4. 2957.5 m2

  5. NA
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Area covered in one revolution = 2 * pi * r * h = 2 * (22/7) * 0.49 * 1.6 = 4.928 m^2. Total area = 600 * 4.928 = 2956.8 m^2.

AI explanation

The area covered by the cylindrical roller is its curved surface area multiplied by the number of revolutions. The curved surface area of the cylinder is 2 times pi times r times h, which is 2 times 22 divided by 7 times 49 times 160, resulting in 49280 cm2. Multiplying this by 600 revolutions gives 29568000 cm2. Converting this to square meters by dividing by 10000 gives an area of 2956.8 m2.

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