Multiple choice

The ratio of water and milk in a container was 5 : 7 on Sunday. On Monday, some amount of water was added. On Tuesday, some more amount of water was added. If the amount of water added on Monday and Tuesday was in the ratio 5 : 7, then what was the ratio of water and milk on Tuesday if the amount of water in the container on Monday had increased by 70% from its value on Sunday?

  1. 51 : 91

  2. 67 : 35

  3. 71 : 36

  4. 81 : 42

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Sunday: W=5k, M=7k. Monday: W increases by 70% of 5k = 3.5k. Total W = 8.5k. Added water on Monday = 3.5k. Ratio of Mon/Tue added water = 5:7. Tue added = 3.5k * 7/5 = 4.9k. Total W on Tuesday = 8.5k + 4.9k = 13.4k. Ratio W:M = 13.4k : 7k = 134:70 = 67:35.

AI explanation

Let the initial amounts of water and milk be 50 litres and 70 litres, respectively, to maintain the 5 to 7 ratio. Since water on Monday increased by 70% from its Sunday value, 35 litres of water was added. Given that the water added on Monday and Tuesday is in the ratio 5 to 7, the volume added on Tuesday is 35 multiplied by 7/5, which equals 49 litres. The total final quantity of water becomes 50 plus 35 plus 49, resulting in 134 litres against the original 70 litres of milk, making the final ratio 67 to 35.

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