Multiple choice

The water level in a cylindrical beaker, having a base radius 10 cm, is at a height of 14 cm from the base. If a metallic sphere of radius 3 cm is put into this beaker, what will be the rise in the water level?

  1. 0.36 cm

  2. 0.63 cm

  3. 1.36 cm

  4. 1.63 cm
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Volume of sphere = 4/3 * pi * r^3 = 4/3 * pi * 27 = 36 * pi. Rise in water level h in a cylinder: pi * R^2 * h = 36 * pi. With R = 10, 100 * h = 36, so h = 0.36 cm.

AI explanation

The volume of the metallic sphere is calculated using the formula 4 thirds times pi times 3 cubed, which equals 36 times pi. When placed in the cylindrical beaker, this volume raises the water level, so the volume of the displaced water equals the volume of the sphere. The rise in water level is found by dividing 36 times pi by the base area of the cylinder, pi times 10 squared, which gives 0.36 centimeters. The rise in the water level is 0.36 centimeters.

Keep practicing — related questions