Multiple choice

2 smaller circles touch a large circle internally and pass through the centre O of the larger circle. If the diameter of the bigger circle is 28 cm, then what is the area of the bigger circle which is not enclosed by the 2 smaller circles (in cm2)?

  1. 154

  2. 256

  3. 308

  4. 616
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Large circle radius R = 14. Area = pi * 14^2 = 196*pi. Smaller circles have diameter 14, so radius r = 7. Area of two smaller circles = 2 * (pi * 7^2) = 98*pi. Remaining area = 196*pi - 98*pi = 98*pi = 98 * 22/7 = 308.

AI explanation

The radius of the larger circle is 14 cm, making its area 616 square cm. Since the two smaller circles pass through center O and touch the larger circle internally, their diameters equal the larger radius of 14 cm, giving each a radius of 7 cm. The combined area of the two smaller circles is 308 square cm. Subtracting this from the larger circle's area leaves 308 square cm.

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