Multiple choice

There is a single road between two cities P and Q. Two buses start running from these cities P and Q towards each other with speeds of 90 kmph and 108 kmph, individually. What will be the distance between the two buses 10 s before they come face to face?

  1. 550 m

  2. 330 m

  3. 440 m

  4. 660 m
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A Correct answer
Explanation

Relative speed = 90 + 108 = 198 kmph. Convert to m/s: 198 * (5/18) = 55 m/s. In 10 seconds, the distance covered is 55 * 10 = 550 m. This is the distance between them 10 seconds before they meet.

AI explanation

To find the distance 10 seconds before collision, we calculate the relative distance covered in that time. Using the relative speed method for objects moving in opposite directions, the relative speed is 90 kmph plus 108 kmph, totaling 198 kmph. Converting this to meters per second gives 198 multiplied by 5/18, which equals 55 m/s. Multiplying this relative speed by 10 seconds gives a distance of 550 m.

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