A milkman, at the end of his day, has a mixture of milk and water left in his can in the ratio 4 : 5. Next morning, if he fills the can with an additional 8 litres of milk to make it full, the ratio of milk and water would become 6 : 5. Find the capacity of the can (in litres).

Let the initial volume of milk and water be 4y and 5y. When 8 litres of milk is added, the new ratio becomes (4y + 8) / 5y = 6 / 5. Solving this equation gives 20y + 40 = 30y, which means y equals 4. The initial total volume was 9y, which is 36 litres. Adding the 8 litres of milk gives a total capacity of 44 litres.

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