In a container that can carry 32 kg, Rahul has a mixture of wheat and rice, wheat being 64% of the total quantity. After taking out some quantity of the mixture, he adds equal quantity of rice in the mixture. He repeats this process twice. Now, the wheat is 16% only. How much mixture is taken out by Rahul every time?

The initial amount of wheat in the container is 64% of 32 kg, which equals 20.48 kg, and the final amount is 16% of 32 kg, which equals 5.12 kg. Using the replacement formula where the final amount equals the initial amount multiplied by the quantity remaining divided by the total quantity raised to the power of the number of replacements, we set 5.12 equal to 20.48 multiplied by the factor (32 minus x) divided by 32, with the whole fraction squared. Solving this gives the factor squared as 0.25, so the factor itself is 0.5, which means 32 minus x equals 16. The quantity of mixture taken out each time is 16 kg.

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