Multiple choice

Find the probability of the first draw that gives 4 red candies and the second draw that gives 4 blue candies from a bag that contains 6 red and 9 blue candies, if two successive drawings of four candies are made, so that the candies are not replaced before second draw.

  1. 55 441

  2. 86 441

  3. 3 715

  4. 4 715

  5. 6 715

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The probability is calculated by (ways to pick 4 red from 6) * (ways to pick 4 blue from 9) / (total ways to pick 4 from 15) * (total ways to pick 4 from 11). The calculation yields 3/715.

AI explanation

The total number of candies is 15. The probability of drawing 4 red candies first is (6C4)/(15C4) which is 15/1365. The bag then contains 2 red and 9 blue candies, making the probability of drawing 4 blue candies 9C4/11C4 which is 126/330. Multiplying these gives (15/1365) times (126/330), equaling 3/715.