If three dice are rolled, find the number of possible outcomes in which at least one die shows 4.
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If three dice are rolled, find the number of possible outcomes in which at least one die shows 4.
91
100
64
79
Total outcomes = 6^3 = 216. Outcomes with no 4 = 5^3 = 125. Outcomes with at least one 4 = 216 - 125 = 91.
To find the outcomes where at least one die shows 4, use the complementary event approach to calculate the total outcomes minus the outcomes where no die shows 4. The total number of outcomes when rolling three dice is 6 times 6 times 6, which equals 216. The number of outcomes where no die shows a 4 (meaning each die can only land on 1, 2, 3, 5, or 6) is 5 times 5 times 5, or 125. Subtracting the complementary outcomes from the total gives 216 minus 125, leaving 91 possible outcomes.