Using the principle of sets, we first find the multiples of 3 up to 30, which gives 10 numbers, and the multiples of 5 up to 30, which gives 6 numbers. The multiples of both 3 and 5 are the multiples of 15, which gives the numbers 15 and 30, totaling 2 numbers. We subtract the multiples of 15 from the total of the individual sets to find the numbers that are multiples of 3 or 5 but not both, giving 10 plus 6 minus 4, which equals 12. The probability is 12 favorable outcomes divided by 30 total outcomes, simplifying to the result of 2 over 5.