What is the chance that a leap year, selected at random, will contain 53 Sundays?
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What is the chance that a leap year, selected at random, will contain 53 Sundays?
2/7
3/7
1/7
5/7
A leap year has 366 days, which is 52 weeks and 2 extra days. The possible pairs for these 2 extra days are (Sun, Mon), (Mon, Tue), (Tue, Wed), (Wed, Thu), (Thu, Fri), (Fri, Sat), or (Sat, Sun). Out of these 7 equally likely outcomes, 2 contain a Sunday, resulting in a probability of 2/7.
A leap year has 366 days, which equals 52 weeks and 2 extra days. For the year to have 53 Sundays, one of those two extra days must be a Sunday. The possible pairs of extra days are 7 in total, with 2 pairs containing a Sunday, so the probability is 2 / 7.