Multiple choice

A dice is having three letters A, B and C written on its faces. Three faces have A, two have B and one has C written on them. What is the probability that the letters A, B and C appear in the first, second and third tosses, respectively?

  1. 3/36

  2. 6/36

  3. 1/2

  4. 1/36

  5. none above
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

P(A) = 3/6 = 1/2. P(B) = 2/6 = 1/3. P(C) = 1/6. Probability of sequence (A, B, C) = (1/2) * (1/3) * (1/6) = 1/36.

AI explanation

The probability of getting A on the first toss is 3 out of 6, or 1/2. The probability of getting B on the second toss is 2 out of 6, or 1/3, and the probability of getting C on the third toss is 1 out of 6, or 1/6. Because these are independent events, multiply the individual probabilities to get (1/2) times (1/3) times (1/6), which equals 1/36.

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