Multiple choice

Two cars are running along the same road. The first one, which is running at the rate of 30 km/hr, starts 6 hours ahead of the second one, which is running at the rate of 50 km/hr. How much distance would the first car have travelled before the second car catches up? at such time?

  1. 400 k.m.

  2. 450 k.m.

  3. 360 k.m.

  4. 375 k.m.

  5. 470 k. m.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

First car travels 30 km/h for 6 hours before second starts = 180 km. Relative speed = 50 - 30 = 20 km/h. Time to catch up = 180 / 20 = 9 hours. Distance traveled by first car = 180 + (30 * 9) = 180 + 270 = 450 km.

AI explanation

In the 6 hours before the second car starts, the first car builds a lead of 30 multiplied by 6, which equals 180 km. The second car travels at a relative speed of 50 - 30 = 20 km/hr to close this gap. The time taken for the second car to catch up is 180 divided by 20, yielding 9 hours. The total distance travelled by the first car at that time is its speed multiplied by the total time travelled (6 + 9 hours), calculated as 30 * 15. The first car would have travelled 450 k.m.

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