What is the sum of the 10th, 20th, 30th and 40th terms of the sequence: Sn = Sn - 1 - 10, if it is given that S3 = 0?
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What is the sum of the 10th, 20th, 30th and 40th terms of the sequence: Sn = Sn - 1 - 10, if it is given that S3 = 0?
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The recurrence S_n = S_{n-1} - 10 is an arithmetic progression with common difference -10. S_3 = 0, so S_n = 0 - 10(n - 3) = 30 - 10n. Terms: S_10 = -70, S_20 = -170, S_30 = -270, S_40 = -370. Sum = -70 - 170 - 270 - 370 = -880.
Given the recursive formula Sn = Sn - 1 - 10 and S3 = 0, this sequence is an arithmetic progression with a common difference of -10. Using the nth term formula, the 10th term is 0 + (10 - 3)(-10) = -70, the 20th term is 0 + (20 - 3)(-10) = -170, the 30th term is 0 + (30 - 3)(-10) = -270, and the 40th term is 0 + (40 - 3)(-10) = -370. Adding these four terms gives (-70) + (-170) + (-270) + (-370) = -880.