Consider a pack of 52 cards. One card is drawn at random. What is the probability of the card being a heart or a seven?
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Consider a pack of 52 cards. One card is drawn at random. What is the probability of the card being a heart or a seven?
1/52
4/13
1/26
17/52
1/4
Total cards = 52. Hearts = 13. Sevens = 4. One card is a seven of hearts, so it is counted twice. P(Heart or Seven) = P(Heart) + P(Seven) - P(Heart and Seven) = 13/52 + 4/52 - 1/52 = 16/52 = 4/13.
Apply the addition theorem of probability for non-mutually exclusive events to solve for the likelihood of drawing a heart or a seven. The probability of drawing a heart is 13/52, and the probability of drawing a seven is 4/52. Since the seven of hearts is counted in both groups, subtract its probability of 1/52 from the sum. The calculation is 13/52 plus 4/52 minus 1/52, resulting in 16/52, which simplifies to 4/13. The answer is 4/13.