If a pair of dice is thrown, the probability that the sum is neither 7 nor 11 is
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7/9
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5/9
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7/11
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9/11
When rolling two dice, there are 36 possible outcomes. The sum is 7 in 6 cases and 11 in 2 cases, making a total of 8 outcomes for a sum of 7 or 11. The probability of getting a sum of 7 or 11 is 8/36 = 2/9, so the probability of getting neither is 1 - 2/9 = 7/9.
When two dice are thrown, the total number of outcomes is 36. The probability of the sum being neither 7 nor 11 can be found by subtracting the probability of getting a 7 or 11 from 1. There are 6 outcomes that sum to 7 and 2 outcomes that sum to 11, making 8 total favorable outcomes for those two sums. The probability of getting neither is 1 - 8/36, which equals 28/36. Simplifying the fraction by dividing by 4 gives 7/9.