Multiple choice

Sixth term of the series ab, a2b3, a3b5 � is equal to

  1. a6b11

  2. a5b10

  3. a6b6

  4. a5b11
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A Correct answer
Explanation

The exponents follow the pattern a^n and b^(2n - 1) for the nth term. Substituting n = 6 gives a^6b^11.

AI explanation

Analyzing the two progressions separately, the exponents of a form the arithmetic progression 1, 2, 3, while the exponents of b form the arithmetic progression 1, 3, 5. For the sixth term, the exponent of a is 6 and the exponent of b is found by 1 + (5 * 2) = 11. The sixth term is a6b11.

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