A tent is in the form of a right circular cylinder surmounted by a cone. The diameter of the cylinder is 24 m. The height of the cylindrical portion is 11 m, while the vertex of the cone is 16 m above the ground. What is the area of the curved surface for the conical portion?

The radius of the cone is half of the cylinder's diameter, so r = 12 m, and the height of the cone is the total height above ground minus the cylinder height, which is 16 - 11 = 5 m. Using the Pythagorean theorem, the slant height is √(12² + 5²) = 13 m. The curved surface area of the cone is πrl, which calculates to (22/7) × 12 × 13 = 3432/7 square metres.

• Thanks
• Wrong explanation