Multiple choice

12 men and 16 women together can complete a piece of work in 4 days. If it takes 80 days for one man alone to complete the same work, then how many days would be required for one woman alone to complete the same work?

  1. 160 days

  2. 150 days

  3. 130 days

  4. 175 days

  5. Na
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

1 man = 1/80 work/day. 12 men = 12/80 = 3/20 work/day. Total work = 1/4 per day. 16 women = 1/4 - 3/20 = 5/20 - 3/20 = 2/20 = 1/10 per day. 1 woman = 1/(16 * 10) = 1/160 work/day. So, 160 days.

AI explanation

Since 12 men and 16 women finish the work in 4 days, their combined one-day work is 1 over 4. One man completes the work in 80 days, meaning 12 men complete 12 over 80, or 3 over 20, of the work in one day. Subtracting this from the total one-day work leaves the work done by 16 women in one day as 1 over 4 minus 3 over 20, which is 2 over 20 or 1 over 10. Thus, one woman completes 1 over 160 of the work in one day, meaning she alone requires 160 days.

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