Multiple choice

Ravi and Ajay start simultaneously from the place A for B which is 60 km apart. Ravi's speed is 4 km/hr less than that of Ajay. Ajay after reaching at B, returns and meets Ravi at a place 12 km away from B. Ravi's speed is

  1. 12 km/hr

  2. 10 km/hr

  3. 8 km/hr

  4. 6 km/hr
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let Ajay's speed be v. Ravi's speed is v-4. Ajay travels 60 km to B and then 12 km back, total 72 km. Ravi travels 60-12 = 48 km. Since they start and meet at the same time, 72/v = 48/(v-4). Solving this gives 72(v-4) = 48v, 72v - 288 = 48v, 24v = 288, v = 12. Ravi's speed is 12-4 = 8 km/hr.

AI explanation

Ajay travels 60 km to point B and returns 12 km to meet Ravi, covering a total of 72 km. Ravi covers the remaining distance, which is 60 - 12 = 48 km, in the exact same time, making the ratio of their speeds 72:48 or 3:2. Because Ravi's speed is 4 km/hr less than Ajay's, one unit in this ratio equals 4 km/hr, meaning Ravi's speed is 2 * 4 = 8 km/hr.

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