Multiple choice

A man earns 6% simple interest on his deposits in bank A while he earns 8% simple interest on his deposits in bank B. If the total interest he earns is Rs.1800 in three years on an investment of Rs.9000, what is the amount invested at 6%?

  1. 8000

  2. 6000

  3. 4000

  4. 3000
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let x be the amount at 6%. Then (9000-x) is at 8%. Interest = (x * 0.06 * 3) + ((9000-x) * 0.08 * 3) = 1800. 0.18x + 2160 - 0.24x = 1800. 0.06x = 360. x = 6000.

AI explanation

Let the amount invested at 6 percent be x; then the amount invested at 8 percent is (9000 - x). The total interest equation for three years is (x * 6 * 3) / 100 + ((9000 - x) * 8 * 3) / 100 = 1800, which simplifies to 18x + 216000 - 24x = 180000. Solving 6x = 36000 gives the amount invested at 6 percent as Rs. 6000.

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