What is the sum of 31st and 13th terms of the sequence given below? 2, 7, 12, ...
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What is the sum of 31st and 13th terms of the sequence given below? 2, 7, 12, ...
210
212
213
214
Sequence is arithmetic with a=2, d=5. Term n = a + (n-1)d. 31st term = 2 + 30*5 = 152. 13th term = 2 + 12*5 = 62. Sum = 152 + 62 = 214.
The given sequence is an arithmetic progression with the first term a as 2 and the common difference d as 5. Using the arithmetic progression nth term formula, Tn = a + (n - 1)d, the 31st term is 2 + 30(5) = 152 and the 13th term is 2 + 12(5) = 62. Adding these two terms together gives the sum of 152 + 62 = 214.