What is the 31st term of the given sequence? 3, 7, 11, ...
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What is the 31st term of the given sequence? 3, 7, 11, ...
119
121
123
127
This is an arithmetic progression with a = 3 and d = 4. The n-th term is a + (n-1)d. For n = 31, term = 3 + (31-1) * 4 = 3 + 30 * 4 = 3 + 120 = 123.
This sequence is an arithmetic progression with a first term of 3 and a common difference of 4. Using the formula for the nth term of an arithmetic progression, Tn = a + (n - 1)d, we substitute the known values. For the 31st term, the calculation is 3 + (31 - 1) * 4, which simplifies to 3 + 120 = 123. The 31st term is 123.