Multiple choice

What is the product of 132nd and 130th term of the given sequence? 0, 3, 6, 9, ...

  1. 152491

  2. 152391

  3. 152191

  4. 152091
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D Correct answer
Explanation

The sequence is 0, 3, 6, 9... which is an AP with a=0 and d=3. The n-th term is 3(n-1). The 132nd term is 3(131) = 393. The 130th term is 3(129) = 387. The product is 393 * 387 = 152091.

AI explanation

The given sequence is an arithmetic progression with a first term (a) of 0 and a common difference (d) of 3. Using the formula Tn = a + (n - 1)d, the 132nd term is 0 + (131)(3) = 393, and the 130th term is 0 + (129)(3) = 387. Multiplying these two terms gives 393 * 387 = 152091.

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