What is the 14th term of the given sequence? 3, 6, 9, 12, ...
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What is the 14th term of the given sequence? 3, 6, 9, 12, ...
34
36
39
42
The sequence is an arithmetic progression with first term a=3 and common difference d=3. The nth term is a + (n-1)d. For n=14, 3 + (13 * 3) = 3 + 39 = 42.
The given sequence is an arithmetic progression with the first term a as 3 and the common difference d as 3. Using the formula for the nth term of an arithmetic progression, Tn = a + (n - 1)d, we substitute the values to get T14 = 3 + (14 - 1)3. Solving this gives 3 plus 39, which equals 42.