Multiple choice

If Jatin walks from his house to school at the rate of 6 km/hr, then he reaches school 12 minutes earlier than the scheduled time. However, if he walks at the rate of 4 km/h, then he reaches 13 minutes late. Find the distance of his school from his house.

  1. 5 km

  2. 6 km

  3. 7 km

  4. 8 km

  5. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let distance be D. (D/4) - (D/6) = (12+13)/60 = 25/60 = 5/12. (3D - 2D)/12 = 5/12. D = 5 km.

AI explanation

Using the constant distance formula, the distance equals the product of the two speeds and the total time difference divided by the difference of the speeds. The speeds are 6 km/hr and 4 km/hr, and the total time difference is 12 minutes plus 13 minutes, which equals 25 minutes or 25/60 hours. The distance equals (6 x 4 x 25/60) / (6 - 4) = 10 / 2 = 5 km. The result is 5 km.