Multiple choice

The present ages (in years) of three cousins are three consecutive even integers. Four years ago, the sum of their ages was 30 years. What is the present age (in years) of the youngest cousin?

  1. 6

  2. 8

  3. 10

  4. 12

  5. 14
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D Correct answer
Explanation

Let ages be x-2, x, x+2. Four years ago: (x-6) + (x-4) + (x-2) = 30. 3x - 12 = 30, 3x = 42, x = 14. Youngest is x-2 = 12.

AI explanation

Let the three present ages be the consecutive even integers x, x + 2, and x + 4. Four years ago, their ages were x - 4, x - 2, and x, and the sum of these ages is given as 30, which gives the equation 3x - 6 = 30. Solving this equation, 3x equals 36, so x equals 12. Since x represents the present age of the youngest cousin, the result is 12.

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