A sequence consists of 50 terms and its 6^th term is -36 and the last term is 140. Find the 37^th term.

We can find the common difference by using the arithmetic progression formula where the nth term equals the first term plus the quantity n minus 1 times the common difference. Since the 6th term is negative 36 and the 50th term is 140, we solve for the common difference to find it is exactly 4. Applying this common difference, the 37th term is calculated as negative 36 plus 4 times the difference between 37 and 6, resulting in negative 36 plus 124, which equals 88.

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